Question

-If 5x-13 y = 3x - 8y, what is the value of X²+y²/x² - y² a) 13/12 b) 1/3,-2 C)√14/2,2 d) none​

Answer 1

Answer:

29/21

Step-by-step explanation:

5x - 13y = 3x - 8y

2x = 13y - 8y

2x = 5y

x / y = 5/2

x ^ 2 / (y ^ 2) = 5 ^ 2 / (2 ^ 2)

x ^ 2 / (y ^ 2) = 25/4

[BY APPLYING COMPONENDO AND DIVIDENDO]

(x²+y²)/(x²-y²)=(25+4)/(25-4)

(x ^ 2 + y ^ 2) / (x ^ 2 - y ^ 2) = 29/21

Answer 2

Answer:

Step-by-step explanation:

5x-13y=3x-8y

2x=13y-8y

2x=5y

x/y=5/2

x²/y²=5²/2²

x²/y²=25/4

[BY APPLYING COMPONENDO AND DIVIDENDO]

(x²+y²)/(x²-y²)=(25+4)/(25-4)

(x²+y²)/(x²-y²)=29/21