Question

if 5x-13y=3x-8y, find the value of X2+y2/x2-y2​

Answer 1

Answer:

29/21

Step-by-step explanation:

5x-13y=3x-8y

=> 5x-3x=13y-8y

=>2x=5y

=>x=5y/2

x^2+y^2/x^2-y^2

=>(5y/2)^2+y^2 / (5y/2)^2-y^2

=> 25y^2/4+y^2 /25y^2/4 -y^2

=> 29y^2/4 /21y^2/4

=> 29/21

Answer 2

solution=>

$= > 5x - 13y = 3x - 8y \\ \\ = > 5x - 3x = 13y -8y \\ \\ = > 2x = 5y \\ \\ = > x = \frac{5y}{2} ...(1$

$= \frac{x { }^{2} + y {}^{2} }{x {}^{2} - y {}^{2} }..(2 \\ \\ eq \: (1 \: x \: value \: put \: in \: (2 \\ \\ = \frac{ (\frac{5}{2}y) {}^{2} + y {}^{2} }{( \frac{5}{2}y) {}^{2} - y {}^{2} } \\ \\ = \frac{ \frac{25}{4}y {}^{2} + y {}^{2} }{ \frac{25}{4}y {}^{2} - y {}^{2} } \\ \\ = \frac{ \frac{29}{4}y {}^{2} }{ \frac{21}{4}y {}^{2} } \\ \\ = \frac{29}{21} ans$

I hope it helps you☺