If 5x-2y=7 and xy=2,then find the value of (5x+2y)^2
Answers
Answered by
0
Step-by-step explanation:
5x-2y=7-------(1)
XY=2----------(2)
x=2/y---------(3)
now in eq1
5(2/y)-2y=7
10/y-2y=7
10-2y=7y
10=7y+2y
10=5y
y=2
from eq3
x=2/2
x=1
so the ans is x=1,y=2
Similar questions