Question

If (5x-3y)^2 = 25 and y=5, then find the value of x.​

Answer 1

Answer:

The value of x is 4

Step-by-step explanation:

ATQ,

(5x - 3y) ^2 = 25

Therefore, we can write it as,

(5x - 3y)(5x - 3y) = 25

When we replace y with 5 we get,

(5x - 15)(5x - 15) = 25

This means that, square of a number will be 25.

Therefore, we know that 5 ^2 is 25.

Thus,( 5x - 15)^2 = 25     and  5x - 15 = 5

Transposing it we get,

x = 4

HOPE THIS HELPS YOU...

Answer 2

Answer:

(5x-3y)²= 25. Value of y = 5

(5x-3*5)²= 25

(5x-15)² = 25

(5x)²-2×5x×15 +(15)²= 25. ( Since (a-b)²= (a)²-2ab+(b)²)

25x²-150x+225= 25

25x²-150x+225-25= 0. (Mid term splitting)

25x²-150x+200 = 0

25x²-100x-50x+200 = 0

25x(x-4)-50(x-4)= 0

(25x-50) (x-4) = 0

either x = 25x-50 = 0

x = 50/25 = 2

or x= 4

But when we verify the correct value of x is 2.

Therefore x= 2

Hope it helps you ☺️☺️☺️