Question

if 5x=4y then find the value of the ratio 3x^2+y^2/ 3 x^ 2- y^2​

Answer 1

Step-by-step explanation:

x+2y

3x+4y

=

4

9

9x+18y=12x+16y

2y=3x

y=

2

3

x

We have to find ratio of

3x−y

3x+5y

=

4

9

Putting y=

2

3

x in it

3x−

2

3

x

3x+

2

15

x

=

2

3

x

2

21

x

=

1

7

=7:1

Answered By

Answer 2

Given:

5x=4y

To Find:

the value of the ratio 3x²+y²/3x²-y²

Solution:

To find the value of the ratio, solve the equation.

5x = 4y ..(i)

3x²+y²/3x²-y² ..(ii)

By equation(i) and (ii)

⇒ $\frac{3x^{2} +y^{2} }{3x^{2} -y^{2} } =\frac{5}{4}$

Using the cross multiplication method,

⇒ 12x²+4y² = 15x²-5y²

⇒ 3x² = y²

Now, to find the ratio

$\frac{3x^{2} +y^{2} }{3x^{2} -y^{2} } = \frac{5}{4}$

Putting y² = 3x³,

⇒ 3x²+3x²/3x²-3x² = 5/4

⇒ 24x² = x²

⇒ 24:1

Therefore, the ratio is 24:1.