if 5x+7y=22 and 7x+5y=14,then x+y=
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5x+7y = 22---eq.1
7x+5y = 14---eq.2
multiple the eq.2 by 5 and eq.1 by 7
=> 35x+49y = 154 ---eq.3
=> 35x+25y = 70---eq.4
now subtract eq. 4 from eq.3
=> 35x+49y - 35x-25y = 154 - 70
=> 24y = 84
=> y = 3.5
now put the value of y in eq.1
=> 5x+7(3.5) = 22
=> 5x = 22-24.5
=> 5x = -2.5
=> x = -0.5
so that x + y = -0.5+3.5
=> x+y = 3
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