Question

if 5x+ky+7=0,x+2y-3=0 has no solution then k=​

Answer 1

Answer:

The  required value of k is 5

Step-by-step explanation:

If 5x+ky+7=0,x+2y-3=0 has no solution then k=​

Concept used:

$\boxed{\text{If the equations}\:a_1x+b_1y=c_1\:\text{and}\:a_2x+b_2y=c_2\:\text{have no solution, then }\:\\a_1b_2-a_2b_1=0}$

Now,

$a_1b_2-a_2b_1=0$

$(5)(2)-(k)(2)=0$

$5-k=0$

$\implies\:\boxed{k=5}$