Question

If 5x =sec theta and 5/x=tan theta find 5(xsquare-1/xsquare)

Answer 1

sec²θ - tan²θ = 1
=> (5x)² - (5/x)² = 1
=> 25x² - 25/x² = 1
=> 25 ( x² - 1/x² ) = 1
=> 5 x 5 ( x² - 1/x² ) = 1
=> 5 x ( x² - 1/x² ) = 1/5.

Answer 2

sec²θ - tan²θ = 1

=> (5x)² - (5/x)² = 1

=> 25x² - 25/x² = 1

=> 25 ( x² - 1/x² ) = 1

=> 5 x 5 ( x² - 1/x² ) = 1

=> 5 x ( x² - 1/x² ) = 1/5.

Hope this help you