If 5x =sec theta and 5/x=tan theta find 5(xsquare-1/xsquare)
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Hii..
Answer is in attachment..
hope this helps :)
Answer is in attachment..
hope this helps :)
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x^2=sec^2theta/25
1/x^2=tan^2theta25
=5(sec^x-tan^x)/25=1/5
1/x^2=tan^2theta25
=5(sec^x-tan^x)/25=1/5
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