if 5x= sec theta and 5/x = tan theta ,then find the value of 5 [ x square- 1/x square]
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25x² = sec²Theta
25/x²=tan²theta
25(x²-1/x²)=1-sin²theta/cos²theta
25(x²-1/x²)=cos²theta /cos²theta
5(x²-1/x²)=1/5
25/x²=tan²theta
25(x²-1/x²)=1-sin²theta/cos²theta
25(x²-1/x²)=cos²theta /cos²theta
5(x²-1/x²)=1/5
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