Question

If 5x2-13xy+6y2=0, then find x

Answer 1

5x2 - 13xy + 6y2 = 0 => 5x2 - 10xy - 3xy + 6y2 = 0 => 5x(x - 2y) - 3y(x - 2y) = 0 => (x - 2y) (5x - 3y) = 0 .=>x=2y, x=3y/5

Answer 2

hi friend,

Question: If 5×2-13xy+6y2=0 , then find x

Solution: 5x2 - 13xy + 6y2 = 0 => 5x2 - 10xy - 3xy + 6y2 = 0 => 5x(x - 2y) - 3y(x - 2y) = 0 => (x - 2y) (5x - 3y) = 0 => x = 2y or 5x = 3y => x/y = 2/1 or x/y = 3/5 Therefore, (x : y) = (2 : 1) or (3 : 5)