Question

if 5x²-kx+11=0 has a root x=3, then k=?

Answer 1

Heya^_^


5x^2-kx+11=0. a root x=3 ,

put value of x=3 in that equation,


5(3)^2-k(3)+11=0
9•5-3k+11=0
45-3k+11=0
-3k=-56
k=56/3=18.6


Tháñkß ♥️♥️☺️✌️

Answer 2

Answer:

Step-by-step explanation:

5x^2-kx+11=0

5(9)-k(3)+11=0

45-3k+11=0

-3k= -11-45

-3k= -56

K =-56/-3

K= 18.6