If 5y + 1/5y =6 find 5y–1/5y
Question no 6
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=> 5y + 1/5y = 6
Squaring both sides.
=> [ 5y + 1/5y ]² = [ 6 ]²
[ 5y + 1/5y ]² compare with [ a + b ]²
[a + b ]² = a² + 2ab + b²
so,
=> (5y)² + 2(5y × 1/5y) + (1/5y)² = 36
=> 25y² + 2 + 1/25y² = 36
=> 25y² + 1/5y² + 2 = 36
=> 25y² + 1/5y² = 36 - 2
=> 25y² + 1/5y² = 34
substracing 2 both sides.
=> 25y² + 1/5y² - 2 = 34 - 2
=> 25y² - 2 + 1/5y² = 32
25y² - 2 + 1/5y² compare with
a²-2ab + b²
so, we know a²-2ab + b² = [a - b]²
hence,
=> [ 5y - 1/5y]² = 32
=> 5y - 1/5y = √32
=> 5y - 1/5y = √2×2×2×2×2
=> 5y - 1/5y = 4√2 or 2√8
i hope it helps you.
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