Question

if (5z/6)+(3z/4)=19/12, the value of z is​

Answer 1

Step-by-step explanation:

(5z/6)+(3z/4) = 19/12

LCM of 6 and 4 is 12.

so,(5z×2)/12 + (3z×3)/12 = 19/12

that is,(10z/12) + (9z/12) =19/12

that is,(10z+9z)/12 = 19/12

that is,19z/12 = 19/12

hence,z = 19×12/12×19 =1

hence, the value of z is 1

Answer 2

Answer:

z = 1

Step-by-step explanation:

We have,

(5z/6) + (3z/4) = (19/12)

Taking LCM (6, 4) = 12

So,

(5z/6) × (2/2) = (10z/12)

(3z/4) × (3/3) = (9z/12)

Thus, it becomes

(10z/12) + (9z/12) = (19/12)

(10z + 9z)/12 = (19/12)

(19z/12) = (19/12)

19z = (19/12) × 12

19z = 19

z = 19/19

z = 1

Hence,

z = 1

Hope it helped and believing you understood it........All the best