If 6.023*10 molecules of n2 react completely with h2 calculate molecules
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1 mol of any substance contains exactly 6.022×10^23 molecules hence then 6.022×10^23 molecules occupies 1 mol.
means 1 mole of N2 reacting with H2.
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N2 + 3H2 -------> 2NH3
according to the balanced chemical reaction 1 mol of N2 reacts with 3 moles of H2 and gives 2 mole of NH3.
molecules = number of moles × 6.022×10^23
molecules = 2 × 6.022 × 10^23
molecules = 12.044 × 10^23
molecules = 1.2044 × 10^24
so your answer is 1.2044 × 10^24 molecules of NH3 .
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