Question

if 6/3√2-3√3=a√2+b√3 find the value of a and b
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Answer 1

Answer:

Step-by-step explanation:

6/3 $\sqrt{2}$ - 3 $\sqrt{3}$ = a $\sqrt{2}$  + b $\sqrt{3}$

Since 6/3 is there in place of a, a= 2

in place of b there is  -3, the value of b= -3