Chemistry, asked by ks8769178, 2 months ago

if 6.3 G of NaHCO3 are added to 15.0 G of CH3COOH solution the residue is found to wait 18.0 gram what is he mass of CO2 released in the reaction​

Answers

Answered by Rajkd180203
0

Answer:

3.3 g of CO2

Explanation:

60 g CH3COOH + 84g NaHCO3 ---> 82 g CH3COONa  + 44 g CO2

Moles of NaHCO3 = 6.3/84 = 0.075

Moles of Ch3COOH = 15/60 = 0.25

NaHCO3 is the limiting reagent.

Moles of CO2 formed are = 0.075

Weight of CO2 = 3.3g

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