Question

if 6.3 g of oxalic acid dihydrate is mixed in 250 ml of h20 . What is the molality of the solution

Answer 1

Answer:

Explanation:

The chemical formula of oxalic acid dihydrate is   HOOC-COOH.2H₂O

now, the molar mass is: 126g/mol

no. of moles of this compound is: $\frac{6.3}{126}$ = 0.05

mass of solvent= 250g, since density of water= 1g/ml

mass of solvent in Kg = $\frac{250}{1000}$ = 0.25kg

I'll give you both molality and molarity

molality= no. of moles of solute/mass of solvent in Kg

so, molality will be: $\frac{0.05}{0.25}$  = 0.2 molal

Molarity= no of moles of solute/volume of solution in L

$\frac{6.3x1000}{126x250}$ = 0.2 Molar

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