If 6.3gm of NaHCO3 are added to 15.0gm of CH3COOH solution, the residue is found to weigh 18.0gm. What is the mass of CO2 released in the reaction..??
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Answer:
refer to the attachment plzz....
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Answered by
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Answer:
NaHCO3 + CH3COOH -----> CH3COONa +
H2O + CO2
Initial mass = 6.3 + 15 = 21.3
Final mass = 18.0 + mass of CO2
According to law of conservation of mass : 21.3 = 18.0 + mass of CO2 ,
Mass of CO2 = 3.3 g
I hope it's helpful
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