if 6+ 4 = 210 then ? +? = 123 please solve this.. It's very important..
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Given,
⇒ 6 + 4 = 210
We know that,
⇒ 6 + 4 = 10 and ( 6 - 4 = 2 ).
Here, we got that final number is formed by difference and sum of numbers and the sum is kept of right side while difference on just right to the sum.
Now,
⇒ ? + ? = 123
So, we have to find 2 numbers such that their difference is 1 and sum is 23.
Let the numbers are 'x' and 'y'.
Now,
⇒ x + y = 23 ----- ( 1 )
" AND "
⇒ x - y = 1 ------- ( 2 ).
By adding ( 1 ) and ( 2 ),
⇒ x + y + x - y = 23 + 1
⇒ 2x = 24
⇒ x = 24 ÷ 2
∴ x = 12.
By substituting the value of ' x ' in ( 1 ),
⇒ x + y = 23
⇒12 + y = 23
⇒y = 23 - 12
∴ y = 11.
Again,
⇒ ? + ? = 123
∴ 12 + 11 = 123.
⇒ 6 + 4 = 210
We know that,
⇒ 6 + 4 = 10 and ( 6 - 4 = 2 ).
Here, we got that final number is formed by difference and sum of numbers and the sum is kept of right side while difference on just right to the sum.
Now,
⇒ ? + ? = 123
So, we have to find 2 numbers such that their difference is 1 and sum is 23.
Let the numbers are 'x' and 'y'.
Now,
⇒ x + y = 23 ----- ( 1 )
" AND "
⇒ x - y = 1 ------- ( 2 ).
By adding ( 1 ) and ( 2 ),
⇒ x + y + x - y = 23 + 1
⇒ 2x = 24
⇒ x = 24 ÷ 2
∴ x = 12.
By substituting the value of ' x ' in ( 1 ),
⇒ x + y = 23
⇒12 + y = 23
⇒y = 23 - 12
∴ y = 11.
Again,
⇒ ? + ? = 123
∴ 12 + 11 = 123.
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