if 6,4,8 and 3 occurs with a frequency 4,2,5 and 1 respectively find the arithmetic mean
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Given distribution = 6,4,8,3.
Given frequencies = 4,2,5,1.
(6 * 4 + 4 * 2 + 8 * 5 + 3 * 1)/(4 + 2 + 5 + 1)
= (24 + 8 + 40 + 3)/(12)
= 75/12
= 6.25.
Therefore the Arithmetic mean = 6.25.
Hope this helps!
Given frequencies = 4,2,5,1.
(6 * 4 + 4 * 2 + 8 * 5 + 3 * 1)/(4 + 2 + 5 + 1)
= (24 + 8 + 40 + 3)/(12)
= 75/12
= 6.25.
Therefore the Arithmetic mean = 6.25.
Hope this helps!
siddhartharao77:
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