If (-6, -4) and (3,5) are the extremities of the diagonal of a parallelogram and (-2, 1) is its third vertex, then its
fourth vertex is
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Answer:
fourth vertex = (-1 , 0)
Step-by-step explanation:
let say fourth vertex = ( x , y)
Then slope of parallell lines are equal
(y - (-4) )/(x - (-6)) = (5 - 1)/(3 -(-2))
=> (y + 4)/(x + 6) = 4/5
=> 5y + 20 = 4x + 24
=> 5y = 4x + 4 eq 1
(y - 5)/(x - 3) = ( -4 - 1)/(-6 -(-2))
=> (y - 5)/(x - 3) = -5/-4
=> (y - 5)/(x - 3) = 5/4
=> 4y - 20 = 5x - 15
=> 4y = 5x + 5 Eq1
4 * eq 1 = 5 * eq2
=> 16x + 16 = 25x + 25
=> 9x = -9
=> x = -1
& y = 0
fourth vertex = (-1 , 0)
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