Question

if 6.5g of zinc reacts with 5.0g o fHCl according to the following reaction Zn+2HCl = ZnCl + H (a) what is the limiting reactant

Answer 1

Answer:

HCl is the limiting reactant.

Explanation:

$6.5\text{ g Zn}*\frac{1\text{ mol}}{65.38\text{ g}}=0.099\text{ mol Zn }*\frac{2\text{ mol HCl}}{1\text{ mol Zn}}=0.198 \text{ mol HCl required to react with 6.5 g Zn}$

$5.0\text{ g HCl } *\frac{1\text{ mol}}{36.458\text{ g}}=0.14\text{ mol HCl }*\frac{1\text{ mol Zn}}{2\text{ mol HCl}}=0.07\text{ mol Zn required to react with 5.0 g HCl}$

HCl is the limiting reactant because if all of HCl reacts with Zn, there will still be an excess of 0.029 mol Zn. There is not enough HCl to react with all of Zn.