If 6.5grams of carbon is heated in air the mass of the product obtained will be either 23.0 grams or 14.0 grams depending on the amount of air present. With what law will this be in accordance ( c=12,o=16)
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Answer:
do not disturb
Explanation:
faltu ka kaam mat karo
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Answer:
thank u for asking the question
Explanation:
Proust's law or the law of definite composition.
6 gram C is 1/2 mole, the remaining 16 gram is 1 mole O, yielding 1/2 mole of CO2.
6 gram C is 1/2 mole, the remaining 8.6 g represents CO. I suspect there is a typo error here, instead of 14.6 it should have been 14.0
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