If 6, 8 and t are Pythagorean Triplets, find t. Find the perfect square of 64?
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t= 10
8 is the perfect square root of 64
8 is the perfect square root of 64
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6^2+8^2=t^2
36+64=t^2
100= t^2
t=10
64 is the perfect square of 8
36+64=t^2
100= t^2
t=10
64 is the perfect square of 8
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