If 6.84g of sugar (sucrose) is dissolved in 36g of water, then total number of hydrogen atoms present in sugar solution will be ?(molecular weight of sucrose = 342u)
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moles of sucrose = 6.84/342= 0.02
molecular formula C12H22O11
no. of moles of H = 22 x 0.02= 0.44
moles of H20 = 36/18= 2
no. of moles of H= 2 x 2= 4
Total no. of H moles= 0.44 + 4= 4.44
for no. of atoms, multiply by 6.023 x 10^23
hope this helps ..
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molecular formula C12H22O11
no. of moles of H = 22 x 0.02= 0.44
moles of H20 = 36/18= 2
no. of moles of H= 2 x 2= 4
Total no. of H moles= 0.44 + 4= 4.44
for no. of atoms, multiply by 6.023 x 10^23
hope this helps ..
Please mark as brainliest
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