Math, asked by srivarsha33, 1 year ago

If 6 and 4374 are in GP , try to insert 5 terms between them.

Answers

Answered by anmolpanda01
0

Answer:

Step-by-step explanation:

Let a = 7

t7 = ar^6 = 4374

dividing the two ar^6/a = 4374/6

                           r^6 = 729

r = 3

Now find ar, ar^2 , ar^3 , ar^4 , ar^5

with the values of a = 7, r - 3....


anmolpanda01: r = 3....
anmolpanda01: Plzzz mark as brainliest
anmolpanda01: its a request
srivarsha33: a is not 7 it shouldbe taken as 6 its already given in text
Answered by shadowsabers03
0

Answer:

±18, 54, ±162, 486, ±1458

Step-by-step explanation:

⇒ We will have to insert 5 terms between 6 and 4374 if they're in GP. So let first term a = 6 and seventh term ar⁶ = 4374.

⇒ Finding the common ratio,

  • ar⁶ / a = 4374 / 6
  • r⁶ = 729
  • r = ⁶√729 = 729^(1/6)
  • r = ± 3.

⇒ Inserting five terms...,

  • ar = 6 × ±3 = ±18
  • ar² = 6 × (±3)² = 54
  • ar³ = 6 × (±3)³ = ±162
  • ar⁴ = 6 × (±3)⁴ = 486
  • ar⁵ = 6 × (±3)⁵ = ±1458

⇒ Thus you can insert either 18, 54, 162, 486, 1458 or -18, 54, -162, 486, -1458.


shadowsabers03: Thanks for marking it as the brainliest.
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