Question

If 6 @ 4 @ 7 = 101 and 2 @ 5 @ 11 = 150, then what is the
value of A in A @ 8 @ 9 = 289?

Answer 1

$6^{2} + 4^{2} + 7 ^{2} = 36 + 16 + 49 = 101$

$2 ^{2} + 5 ^{2} + 11 ^{2} = 4 + 25 + 121 = 150$

Thus, if we take A as a

$a ^{2} + 8^{2} + 9 ^{2} = 289$

$a ^{2} + 64 + 81 = 289 \\ a {}^{2} + 145 = 289 \\ a {}^{2} = 144 \\ a = \sqrt{144}$

Thus, A =a =12

Answer 2

Answer:

the correct answer is 12