Question

if(×-6) is the HCF of x2-2×-24 and ×2-Kx-6 then the value of K is ​

Answer 1

Answer:

Given that (x−6) is the HCF of  x  2

−2x−2y and x  

2

−4x−6(x−6) is factor of both expression

Let f(x 1 )=(x 1 )=x  

12 −2x  

−24and f(x 2 )=x −4x  

−6

Now f(x  )=f(x  )=f(x) 

⇒0=30−6k⇒6k=30∴k=5

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