If ( -6, k) lies on line x +3y = 3, then find the value of k.
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Answered by
6
Answer:
3
Step-by-step explanation:
Given:
(-6,k) lies on the line x+3y=3.
Let (-6,k) be (x,y)
We know that,
If a point lies on the line, then it satisfies the line equation,
so on substituting (-6,k) in the given line equation, we can get the value of k. i.e.,
(-6)+3(k) = 3
-6+3k = 3
3k = 3+6
3k = 9
k = 9/3
k = 3
Therefore, the value of k for which (-6,k) lies on the line x+3y=3 is 3.
Hope it helps you.
Good Luck.
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