if 6 lies between the roots of the equation x^2 + 2(a-3)x + 9 =0
Then a belongs to
1.(-3/4, infinity)
2.( - infinity ,-3/4)
3.( - infinity ,0) u (6, infinity)
4.( -3/4 , 6)
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Answered by
5
roots of eqn are
-2(a-3)+-√[4(a-3)^2-4(2(a-3)))] \2
solve. this let the answer coming be m and n
let m <n
then
m<6<n
solve this inequality
-2(a-3)+-√[4(a-3)^2-4(2(a-3)))] \2
solve. this let the answer coming be m and n
let m <n
then
m<6<n
solve this inequality
Answered by
0
Answer:
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