Question

If 6 liter of h2 and 5.6 liter of cl2 are mixed and exploded in an eudiometer the volume of hcl formed is

Answer 1

$\underline{ \huge \boxed{ \bold{ \mathfrak{ \purple{Answer}}}}} \\ \\ \rm \: \star \: \boxed{ \rm\red{ H_2 + Cl_2 \longrightarrow \: 2HCl}} \: \dag$

=> From this reaction it is clear that 22.4 L of both involved in reaction to form 44.8 L of HCl.

=> As per given question Cl2 is limiting reagent.

=> Therefore amount of product depends on amount of Cl2.

Calculation :

22.4 L Cl2 gives 44.8 L HCl

So, 5.6 L Cl2 gives .....

$\rm V{ \tiny{hcl}} = \frac{5.6 \times 44.8}{22.4} \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \orange{V{ \tiny{hcl}} = 11.2 \: L}}}}} \: \: \red{ \clubsuit}$

Answer 2

Answer:

the answer is 11.2 l of hydrogen it will be solved by mole concept used in chemistry