Question

If 6 men and 10 boys complete a work in 4 days and 4 men and 10 boys can complete the same work

in 5 days, then calculate in how many days the same work will be done by 2 men and 5 boys​

Answer 1

Answer:

10 Days

Explanation:

Let A be the efficiency of a man to do work and B be the efficiency of a boy to do work and x unit is work

therefore when 6 men and 10 boys complete a work in 4 days therefore equation is

A/6 +B/10 = 4 (1)

when 4 men and 10 boys complete a work in 5 days then equation is

A/4 + B/10 = 5 (2)

now by elimination method

A/4 - A/6 = 1

(6A-4A)/24 = 1

2A = 24

A = 12

put in equation 2

12/4 + B/10 = 5

3 + B/10 = 5

B/10 = 2 or B = 20

when 2 men and 5 boys do this work then they complete it in

12/2 + 20/5 = 6 + 4 = 10 days

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Answer 2

10 is the answer 10 days