Question

If 6 men and 8 boys can do a piece
of work in 10 days and 26 men and
48 boys can do the same work in 2
days, what would be the time taken
by 15 men and 20 boys to do the
same type of work?

Answer 1

Answer:

4 days

Step-by-step explanation:

Given that:

6 men and 8 boys can do a piece of work in 10 days  

26 men and 48 boys can do the same in 2 days  

As the all work done is equal,

10(6M + 8B) = 2(26M + 48B)

=> 60M + 80B = 52M + 96B

=> M = 2B

=> B = M/2 ……(1)  

Now Put (1) in 15M + 20B

=> 15M + 10M = 25M

Now, 6M + 8B in 10 days

=> (6M + 4M) 10 = 100M

Then D(25M) = 100M

=> D = 4 days.