Question

If 6 men and 8 boys can do a piece of work in 10 days while 16 men and 16 boys can do the same in 2 days, the time taken by 11 men and 10 boys in doing the same type of work will be:

Answer 1

Step-by-step explanation:

Given that

6 men and 8 boys can do a piece of work in 10 days

26 men and 48 boys can do the same in 2 days

As the work done is equal,

10(6M + 8B) = 2(26M + 48B)

60M + 80B = 52M + 96B

=> M = 2B

=> B = M/2 ……(1)

Now Put (1) in 15M + 20B

=> 15M + 10M = 25M

Now, 6M + 8B in 10 days

=> (6M + 4M) 10 = 100M

Then D(25M) = 100M

=> D = 4 days.

Answer 2

Answer:

i think the question is wrong there must not be 16 men and 16 boys beacuse if there is such like that then efficiency of boys comes in minus nd then answer will comes in minus which is not correct

Step-by-step explanation:

see in photo that efficiency comes negative that's why i don't proceed to do