Question

If 6 men and 8 boys can do piece of work in 10 days while 26 men and 48 boys can do the same in 2 days .what is the time taken by 15 men and 20 boys in doing the same work ?
a.4 days
b.6 days
c.5 days
d.7 days
please answer in full explanation

Answer 1

Hello friend Your ANSWER is Option A :- 4 days

Units of work done is measured in terms of man-days, boy-days etc. you will have to find our the number of man-days and boy-days required to do the job and equal it.

10(6M+ 8B) = 2 (26M + 48B) since the same work is done they will be equal

60M + 80B = 52M + 96B

8M =16 B or M= 2B substitute 2B = M and you will get the total man-days required to do the job and it is

10 (6M +4M) = 100 man days

Similarly substitute 20B as 10M to find out the answer

x(15M+10M) = 100M

Solving this X =4 so 15 men and 20 boys will have to work for 4 days to complete the job.

hope helps ☺️