Question

If 6 men can do a piece of work in 20 days and one man can do the work of two boys, then in how many days can 10 men and 5 boys do the same work?8 days12 days10 daysnone of thesemark fo

Answer 1

6 men -> 20 days
1 man -> 20*6 = 120 days

1 man -> 2 boys -> 120 days
1 boy -> 120*2 -> 240 days

10 men -> 120 / 10 -> 12 days
5 boys -> 240 / 5 -> 48 days

Total time = 12 + 48 = 60 days <== Answer

I hope you got your Answer...

Answer 2

According the question :-

one man can do the work of two boys,

∴ 1 man = 2 boys

6 men = 2 × 6 = 12 boys

10 men and 5 boys =( 10 ×2) + 5 = 25 boys

12 boys can do a piece of work  in = 20 days    (  6 men can do a piece of work in 20 days)

1 boy can do a piece of work in = 12 × 20 days

∴  25 boys can do a piece of work in =( 12 × 20 )÷ 25

                                                               = $\frac{240}{25}$ = 9.6 days.

Hence 10 men and 5 boys do the same work in 9.6 days.

Ans :-none of these .

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