Question

If 6 men can do a piece of work in 30 days of 9 hour each, how many men will it take to do 10 times the amount of work if they work fir 25 days 8 hours.

Answer 1

$\frac{m1 \times d1 \times h1}{w1} = \frac{m2 \times d2 \times h2}{w2} \\ \frac{6 \times 30 \times 9}{w} = \frac{25 \times 8 \times m}{10w} \\ m = \frac{6 \times 30 \times 9 \times 10w}{25 \times 8 \times w} \\ m = 81$
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Answer 2

81 is your answer

Explanation
M1×T1/W1 = M2×T2/W2
6×(30×9)/W =M2×(25×8)/10×W
M2=81