If 6 men or 8 boys can reap a field in 21 days ,in what time will 9 men and 2 boys reap the same field
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Given: 6 men and 8 boys reap a field in 21 days
To find: days needed for 9 men and 21 boys to reap the same field
Solution:
1 man one day work
= 1/21x6
=1/126
one boy one day work
=1/21x8
=1/168
(9 men +2 boys)s one day work
=9/126 +2/168
=1/14 + 1/84
=7/84
=1/12
hence, 9 men and 2 boys can reap a field in 12 days
here in this question, the unitary method is used to get the no of days each man and take to complete their work individually. next, the no of men and boys are multiplied to get the answer
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