Question

If 6 power 10 is computed,what would be the digit in one's place ?

Answer 1

Answer:

For any  n≥1 ,  6n≡6(mod10).  

Proof:

n=1 , true (trivial).

Assuming it true for  n=k , let’s prove it for  n=k+1 :

6k+1=6⋅6k≡6⋅6=36≡6(mod10).  

Proved.

In particular,

6100≡6(mod10),  

therefore the last digit is  6 .

Step-by-step explanation: