Question

If 6 sin^–1(x^2 – 6x + 8.5) = π, then x is equal to (a) 1 (b) 2 (c) 3 (d) 8

Answer 1

Answer is B . this may help you my friend.

Answer 2

Step-by-step explanation:

Step-by-step explanation:6sin^-1(x^2-6x+8.5) = Π

Step-by-step explanation:6sin^-1(x^2-6x+8.5) = Πsin^-1(x^2-6x+8.5) = Π/6

Step-by-step explanation:6sin^-1(x^2-6x+8.5) = Πsin^-1(x^2-6x+8.5) = Π/6sinΠ/6 = (x^2-6x+8.5)

Step-by-step explanation:6sin^-1(x^2-6x+8.5) = Πsin^-1(x^2-6x+8.5) = Π/6sinΠ/6 = (x^2-6x+8.5)1/2 = x^2-6x+8.5

Step-by-step explanation:6sin^-1(x^2-6x+8.5) = Πsin^-1(x^2-6x+8.5) = Π/6sinΠ/6 = (x^2-6x+8.5)1/2 = x^2-6x+8.51 = 2x^2-12x+16 = 0

Step-by-step explanation:6sin^-1(x^2-6x+8.5) = Πsin^-1(x^2-6x+8.5) = Π/6sinΠ/6 = (x^2-6x+8.5)1/2 = x^2-6x+8.51 = 2x^2-12x+16 = 0(x-4) (2x-4) = 0

Step-by-step explanation:6sin^-1(x^2-6x+8.5) = Πsin^-1(x^2-6x+8.5) = Π/6sinΠ/6 = (x^2-6x+8.5)1/2 = x^2-6x+8.51 = 2x^2-12x+16 = 0(x-4) (2x-4) = 0x= 4 or x= 2