If 6 sin theta + 7 cos theta =9 , then tan theta ?
Then find the value of 7cos theta -6 sin theta
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Answer:
given
6 sin theta + 7 cos theta =9(equation 1)
let us assume
7 cos theta - 6 sin theta=k(equation 2)
0
squaring and adding on both sides of equation 1 and 2
(6 sin theta+7 cos theta)^2+ (7 cos theta _ 6 sin theta)^2=9^2+k^2
36 sin^2theta+9 cos square theta + 84 sin theta cos theta + 49 sin ^2 theta + 36 cos^2theta -86 sin theta cos theta=81+k^2
85 sin^2theta + 85 cos^2 theta is equals to 81 + k ^2
85(sin^2 theta + cos^2theta)=81+k^2
85(1)=81+k^2
85=81-k^2
85-81=k^2
4=k^2
2=k
4=k
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