Question

If 6 tables and 10 chairs Cost rupees 3600 find the cost of 8 tables and 2 chairs the cost of 3 tables being equal to the cost of 5 chairs​

Answer 1

Step-by-step explanation:

Here,

let the costt of tables and chairs be x and y

3x= 5y

x= 5y/3 (1)

6x+10y= 3600

6(5y/3)+10y= 3600

10y+10y= 3600

20y= 3600

y= 3600/20= 180

And x= 5y/3= 5×180/3= 5×60= 300

Therefore, cost of 8 tables and 2 chairs= 8×300+2×180

=2400+360= 2760

Answer 2

the cost of 8 tables and 2 chairs is 2760

Step-by-step explanation:

let the cost of table be x and chair be y

A/c to condition 1st,

6x+10y=3600

A/c to condition 2nd,

3x =5y

x=5y/3

now, substitute the value of x in equation 1st

6x+10y=3600

6(5y/3)+10y=3600

10y+10y=3600

20y=3600

y= 180

put the value of y in x=5y/3

x=5(180)/3

x=300

Now, the cost of 8 tables and 2 chairs is

8x+2y

8(300) + 2(180)

2400+360

2760