Question

If 6 tan A = 5 then verify that 2 sin A cos A / cos2 A - sin2 A = 60/11​

Answer 1

Step-by-step explanation:

6 tan A = 5

tan A = 5/6

tan A = Perpendicular/Base

Perpendicular = 5. and Base = 6

By Pythagoras theorem

Hypotenuse ² = Base² + perpendicular ²

Hypotenuse ² = 6² + 5²

Hypotenuse ² = 36 + 25

Hypotenuse ² = 61

Hypotenuse = √61

Find the value of Sin A and Cos A

Sin A = perpendicular / hypotenuse

SinA = 5/√61

Cos A = Base / hypotenuse

Cos A = 6/√61

2 sin A cos A / cos2 A - sin2 A = 60/11

Let's solve LHS

2×5/√61×6/√61 / 6/√61×2-5/√61 ×2

60/61/8/√61-10/√61

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