Question

if 6 tanA = 5 find 3sinA - cosA + 9sinA​

Answer 1

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MATHS

If 6tanA−5=0, find the value of:

6cosA+sinA

3sinA−cosA

is

m

9

, then m is

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ANSWER

6tanA−5=0

tanA=

6

5

Now,

6cosA+sinA

3sinA−cosA

Multiply and divide by cosA

=

6+tanA

3tanA−1

=

6+

6

5

3(

6

5

)−1

=

6

41

2

5

−1

=

6

41

2

5−2

=

41

9