Question

if 6 term of an ap is 26 and 10th term is 38.find the common difference

Answer 1

The formula of ap is n = a + (n-1) d

So t6= a + 5d = 26 ....... ( 1 )

T10 = a+ 9d = 36 ....... (2)

So subtracting 2 from 1 we got

4d = 10

D = 10/4 = 5/2 = 2.5

Hence the common diff. Is 2.5

Answer 2

Answer:

Common difference (d) = 3

Step-by-step explanation:

We know that the nth term of the arithmetic progression is given by a+(n−1)d

Given that 6th term of an A.P. is 26

Therefore, a+(6−1)d = 26

⟹a+5d = 26 ---------(1)

Given that 10th term of an A.P. is 38

Therefore, a+(10−1)d = 38

⟹a+9d = 38 ---------(1)

subtracting eqn (2) from eqn (1) gives (a+9d) − (a+6d) = 38 - 26

⟹4d = 12

⟹d = 3

∴Common difference (d) = 3