Question

If 6 times of the sixth term of an A.P. is equal to 13 times its thirteenth term,
find the nineteenth term?​

Answer 1

Step-by-step explanation:

that is a6 = 0

a + 5d = 0

a = -5 d

Now, a15 = a + (n – 1 )d

a + (15 – 1)d = -5d + 14d = 9d

and a33 = a + (n – 1 )d

= a + (33 – 1)d

= -5d + 32d

= 27d

Now, a33 : a12

27d : 9d

3 : 1

Which shows that a33 = 3(a1

Hope this helps you buddy