if 6 x^4+ 8 x^3- 5x^2 + a x + b is divisible by 2x^2 - 5 find a and b
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Answer:
a = -20, b = -25
Step-by-step explanation:
Here are a couple of approaches. Use whichever is appropriate for your class work.
Method 1
Doing long division, we get
6x⁴ + 8x³ - 5x² + ax + b = ( 2x² - 5 ) ( 3x² + 4x + 5 ) + (20+a)x + (b+25).
As the remainder is zero, we have
20 + a = 0 => a = -20
and
b + 25 = 0 => b = -25
Method 2
Let x be assigned a value such that 2x² - 5 = 0. Then...
6x⁴ + 8x³ - 5x² + ax + b = 0
=> 3(2x²)(2x²) + 8x(2x²) - 5(2x²) + 2ax + 2b = 0
=> 3(5)(5) + 8x(5) - 5(5) + 2ax + 2b = 0
=> 75 + 40x - 25 + 2ax + 2b = 0
=> (20+a)x + (25+b) = 0.
As this holds for two different values of x (the two solutions of 2x²-5=0), it follows that
20 + a = 0 => a = -20
and
25 + b = 0 => b = -25
Anonymous:
You're welcome. Glad to have helped!
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