If 60% of a first order reaction was completed in 60 min, 50% of the same reaction would be completed in approximately
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If the 60% of first order reaction was completed in 60 minutes, 50 % of the same reaction would be completed in approximately (log 4 = 0.6, log 5 =0.69) 1- 45 mins. 2- 60 mins. 3-40 mins.
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