Question

if 60% of a first order reaction was completed in 60 minutes 50% of the same reaction would be completed in approximately​

Answer 1

Answer:

45 min.

Explanation:

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Answer 2

If 60% of a first order reaction was completed in 60 minutes 50% of the same reaction would be completed in approximately​ 46 minutes

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

k = rate constant  = ?

t = time for decay  = 60 minutes

a = let initial amount of the reactant  = 100 g

x = amount decayed = 60 g

a - x = amount left after decay process  = 100 - 60 = 40

Now put all the given values in above equation, we get

$60=\frac{2.303}{k}\log\frac{100}{40}$

$k=0.015min^{-1}$

Now time for the reaction to be 50% complete:

$t=\frac{2.303}{0.015}\log\frac{100}{100-50}$

$t=46minutes$

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